2x^2+4x-9=2(x-1)2

Solution for 2x^2+4x-9=2(x-1)2 equation:

Simplifying
2x2 + 4x + -9 = 2(x + -1) * 2

Reorder the terms:
-9 + 4x + 2x2 = 2(x + -1) * 2

Reorder the terms:
-9 + 4x + 2x2 = 2(-1 + x) * 2

Reorder the terms for easier multiplication:
-9 + 4x + 2x2 = 2 * 2(-1 + x)

Multiply 2 * 2
-9 + 4x + 2x2 = 4(-1 + x)
-9 + 4x + 2x2 = (-1 * 4 + x * 4)
-9 + 4x + 2x2 = (-4 + 4x)

Add '-4x' to each side of the equation.
-9 + 4x + -4x + 2x2 = -4 + 4x + -4x

Combine like terms: 4x + -4x = 0
-9 + 0 + 2x2 = -4 + 4x + -4x
-9 + 2x2 = -4 + 4x + -4x

Combine like terms: 4x + -4x = 0
-9 + 2x2 = -4 + 0
-9 + 2x2 = -4

Solving
-9 + 2x2 = -4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 2x2 = -4 + 9

Combine like terms: -9 + 9 = 0
0 + 2x2 = -4 + 9
2x2 = -4 + 9

Combine like terms: -4 + 9 = 5
2x2 = 5

Divide each side by '2'.
x2 = 2.5

Simplifying
x2 = 2.5

Take the square root of each side:
x = {-1.58113883, 1.58113883}